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Basic Question 3 of 10
We want to test the claim that a steady diet of wolfsbane will cause an 18-year-old werewolf to lose EXACTLY 10 lbs. over 5 months. A random sample of 49 werewolf was taken, yielding an average weight loss over 5 months of 12.5 lbs with S = 7 lbs. Let alpha = .02. What is the calculated value suitable for testing the above hypothesis?
B. 7 x 2.5
C. 2.5
A. 12.5
B. 7 x 2.5
C. 2.5
User Contributed Comments 9
| User | Comment |
|---|---|
| isida | test statistic question: (sample statistic - null value) / standard error standard error = standard deviation / sqrt N |
| Masterkang | Obviously, he read to many Harry Potter Books... |
| achu | we know it's t-test because S sample sd, not population std dev. |
| steved333 | Yes, but sample size is large, so it doesn't matter. T-stat is the same as Z in this case. |
| poomie83 | Was alpha there as useless information? |
| ybavly | @poomie83 yes |
| johntan1979 | Agree with steved333. n>30, so Z. |
| sgossett86 | the equation for variance is single bernoulli variable |
| Shaan23 | You guys need to read the notes. One we dont know if this is normal or not. Population variance is unknown. Whenever population variance is unknown always jump to t-test. But remember t-test approaches the z test when n becomes big. |
Your review questions and global ranking system were so helpful.
Lina
Learning Outcome Statements
explain hypothesis testing and its components, including statistical significance, Type I and Type II errors, and the power of a test
CFA® 2024 Level I Curriculum, Volume 1, Module 8.