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Basic Question 4 of 13
For the hypothesis test shown below, the decision should be to ______.
B. fail to reject H0
C. reject H0
A. conclude Ha
B. fail to reject H0
C. reject H0
User Contributed Comments 10
| User | Comment |
|---|---|
| Yurik74 | How -2.33 is calculated??? I understand that -3.71 = (16.1-17)/(2.3/sqrt(90)) |
| surjoy | Z 0.01 is 2.33 |
| JKiro | Yurik74: critical values (rejection points) are determined by the experimenters |
| VGVG | Isn't this a one-tailed test? And for a one-tailed test, the decision rule is: Reject H0 if z > z-alpha. In this case, z-score of -3.71 can't be > -2.33 |
| VGVG | Never mind, this is a one-tailed test with: H0: u >= u0, and for this the rejection clause is: z < -z-alpha |
| thekid | PLeAse ExplAin the following: "Note- the p-value for an x-bar of 16.1 is 0+." How did they get this? What does that mean? |
| bhaynes | thekid: the smaller the p-value, the higher the chance that we are going to reject the null and accept the alternate. For the values above, we can check the z-table for our z-stat of -3.71 and see the p-value of .0001. That's pretty low. That means that we can say with a 99.99% chance, that we should reject the null. Remember......As the p-value shrinks, so does our confidence in the null. |
| johntan1979 | alpha of .01 for two-tailed is 2.58, one-tailed is 2.33 |
| ldfrench | HAS ANYONE SEEN MY DOG???? |
| farhan92 | hes on the derivatives section... |
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Lina
Learning Outcome Statements
explain hypothesis testing and its components, including statistical significance, Type I and Type II errors, and the power of a test
CFA® 2024 Level I Curriculum, Volume 1, Module 8.