- CFA Exams
- 2023 Level II
- Topic 7. Derivatives
- Learning Module 34. Valuation of Contingent Claims
- Subject 4. Black-Scholes-Merton Option Valuation Model

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##### Subject 4. Black-Scholes-Merton Option Valuation Model PDF Download

**Assumptions of the BSM Model**

- The underlying price follows a lognormal probability distribution as it evolves through time.
- Interest rates remain constant and known.
- The underlying instrument is liquid. The price of the underlying instrument is continuous.
- The volatility of the underlying instrument is known and constant.
- The market is "perfect." There are no transaction costs, regulatory constraints, or taxes. Continuous trading is available. Short selling of the underlying instrument with full use of the proceeds is permitted. There are no arbitrage opportunities in the marketplace.
- There are no cash flows on the underlying. If the underlying instrument pays a yield, it is expressed as a continuous known and constant yield at an annualized rate.
- European exercise terms are used.

**BSM Model**

The Black-Scholes-Merton formulas for the prices of call and put options are:

_{1}) - e

^{-rT }XN(d

_{2}) p = e

^{-rT}XN(-d

_{2}) - SN(-d

_{1})

where:

d

_{1}= {ln(S/X) + [r + (σ

^{2}/2)] T} / [σ (T

^{1/2})]

d

_{2}= d

_{1}- σ (T

^{1/2})

σ = the annualized standard deviation of the continuously compounded return on the stock

r = the continuously compounded risk-free rate of return

N(.) = the cumulative normal distribution function

- N(-x) = 1 - N(x)
- N(d
_{1}) is the basis for the number of units of the underlying instrument needed to replicate an option. It is the primary determinant of delta, and it answers the question of how much the option value will change with a small change in the underlying. - N(d
_{2}) is the probability that the call option expires in the money.

*Example 1*

Assume that a stock trades at $100 and the continuously compounding risk-free interest rate is 6%. A call option on the stock has an exercise price of $100 and expires in one year. The standard deviation of the stock's returns is 0.1 per year. We compute the values of d

_{1}and d

_{2}as follows:

d

_{1}= [ln(100/100) + (0.06 + (0.1

^{2}/2) 1] / (0.1 1

^{1/2}) = 0.65

d

_{2}= 0.65 - 0.1 x 1

^{1/2}= 0.55

Next, we find the cumulative normal values associated with d

_{1}and d

_{2}. These values are the probability that a normally distributed variable with a zero mean and a standard deviation of 1.0 will have a value equal to or less than the d

_{1}or d

_{2}term we are considering. Below is the relevant part of the cumulative probabilities table for a standard normal distribution.

For a value of 0.65 drawn from the border of the table, we find our probability in the interior: N(d

_{1}) = N(0.65) = 0.7422. Similarly, N(d

_{2}) = N(0.55) = 0.7088.

We now have:

c = $100 x 0.7422 - $100 x e

^{-0.06 x 1}x 0.7088 = $7.46

p = $100 x e

^{-0.06 x 1}x (1 - 0.7088) - $100 x (1 - 0.7422) = $1.64

The BSM model can be described as the present value of the expected option payoff at expiration. It can also be described as having two components: a stock component and a bond component.

- For call options, the stock component is SN(d
_{1}) and the bond component is e^{-rT}XN(d_{2}). c = stock - bond = SN(d_{1}) - e^{-rT}XN(d_{2}) - For put options, the stock component is SN(-d
_{1}) and the bond component is e^{-rT}XN(-d_{2}). p = bond - stock = e^{-rT}XN(-d_{2}) - SN(-d_{1})

Investors can replicate the stock option payoffs with stocks and bonds:

_{S}S + n

_{B}B

*Example 2*

Assume d

_{1}= 0.3 and d

_{2}= 0.5. N(d

_{1}) is 0.6179 and N(d

_{2}) = 0.6915.

- To replicate a call option we should buy n
_{S}= N(d_{1}) = 0.6179 shares, and buy -N(d_{2}) = -0.6915 zero-coupon bond (short the bond). - To replicate a put option we should short n
_{S}= -N(-d_{1}) = -(1 - 0.6179) = -0.3821 shares (short the stock), and buy N(-d_{2}) = (1 - 0.6915) = 0.3085 zero-coupon bond. - The price of the zero-coupon bond is B = e
^{-rT}X.

Note that for currency options, the stock component becomes the foreign exchange component. For example, the BSM call model applied to currencies is simply the foreign exchange component minus the bond component.

The BSM model can be adjusted to accommodate carry benefits.

c = Se

^{-γT}N(d

_{1}) - e

^{-rT}XN(d

_{2})

p = e

^{-rT}XN(-d

_{2}) - Se

^{-γT}N(-d

_{1})

where d

_{1}= [ln(S/X) + (r-γ+σ

^{2}/2)T]/(σT,sup>1/2)

Note that d

_{1}, d

_{2}and the stock component are all adjusted for carry benefits.

Carry benefits reduce the value of call option and raise the value of the put option. In replicating strategies, carry benefits lower the number of shares to buy (short) for calls (puts).

- For stock options, the carry benefits are dividends. γ is the continuously compounded dividend yield.
- For currency options, the carry benefits are the continuously compounded foreign interest risk-free rates. The domestic risk-free rate is the risk-free rate to be used in the model.

**Learning Outcome Statements**

interpret the components of the Black-Scholes-Merton model as applied to call options in terms of a leveraged position in the underlying;

describe how the Black-Scholes-Merton model is used to value European options on equities and currencies;

CFA® 2023 Level II Curriculum, Volume 5, Module 34

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**User Contributed Comments**
5

User |
Comment |
---|---|

danlan2 |
Vega (volatility of option) is greated for an option near the money; when an option is deep in or out of the money, vega is low and can approach zero. Rho is positive for call and negative for put; thetas are generally less than zero. |

robertucla |
Long-Term Capital Management! |

philjoe |
lol robert |

myron |
normal distribution: zero is possible, symmetric, and additive. But negative stock values are possible which is not realistic. Lognormal distribution means that log returns are distributed normally. |

myron |
Key assumption for any option valuation models: how to model the random nature of the underlying instrument. |

I used your notes and passed ... highly recommended!