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Subject 2. Unconditional, Conditional, and Joint Probabilities PDF Download
The complement of event A is the event that A does not occur. It is expressed as Ac. The probabilities of an event and its complement must have a sum of 1: P(A) + P(Ac) = 1. Note that event A and its complement, Ac, are mutually exclusive (there is no overlapping of their possible outcomes) and exhaustive (these two events include all possible outcomes). For example, event A refers to an increase in interest rates. The probability of event A is 0.7. Ac is the event that interest rates will not increase. P(Ac) = 1 - 0.7 = 0.3.
P(AB) = P(A|B) x P(B)
Probabilities are either unconditional or conditional.
Unconditional probability, also called marginal probability, is simply the probability of an event occurring. It refers to the probability of an event that is not conditioned on the occurrence of another event. For example, what is the probability that a stock earns a return above the risk-free rate? An unconditional probability can be considered as a stand-alone probability. It is expressed as P(A).
A conditional probability is the probability of an event given that another event has occurred. It is denoted as P(A | B) ("the probability of A given B").
For example, what is the probability that the total of two dice will be greater than 8 if the first dice is a 6? This can be computed by considering only outcomes which could occur if the first dice is a 6 and determining the proportion of these outcomes that total more than 8. There are six outcomes for which the first dice is a 6, and of these, there are four that total more than 8 (6,3; 6,4; 6,5; 6,6). The probability of a total greater than 8, given that the first dice is 6, is therefore 4/6 = 2/3. More formally, this probability can be written as: P(total>8 | Dice 1 = 6) = 2/3. In this equation, the expression to the left of the vertical bar represents the event and the expression to the right of the vertical bar represents the condition. Thus, it would be read as "The probability that the total is greater than 8, given that Dice 1 is 6, is 2/3." In more abstract form, P(A|B) is the probability of event A given that event B occurred.
A joint probability is the probability of both events A and B happening together. It is denoted as P(AB) ("the probability of A and B"). For example, Kevin is assessing the probability that both airfare and oil prices increase. Such a probability is a joint probability.
If two events are mutually exclusive, then they cannot occur together, so the joint probability of two mutually exclusive events is 0.
A joint probability function of two random variables, X and Y, gives the probability of joint occurrences of the values of X and Y.
If we know the conditional probability P(A|B) and we want to know the joint probability P(AB), we can use the following multiplication rule for probabilities:
If someone draws a card at random from a deck and then, without replacing the first card, draws a second card, what is the probability that both cards will be aces? Event A is that the first card is an ace. Since 4 of the 52 cards are aces, p(A) = 4/52 = 1/13. Given that the first card is an ace, what is the probability that the second card will be an ace as well? Of the 51 remaining cards, 3 are aces. Therefore, p(B|A) = 3/51 = 1/17 and the probability of A and B is: 1/13 x 1/17 = 1/221.
The probability of an increase in oil price, P(B), is 0.4. The probability of an increase in airfare given an increase in oil price, P(A|B), is 0.3. The joint probability of an increase in both oil price and airfare, P(AB), is 0.3 x 0.4 = 0.12.
- Look out for the words "given that" or "you are told that," which will help you know that the probability is conditional. In the absence of such information, the probability will be unconditional.
- The letter after the | is the event that we know has definitely occurred, whereas the letter before the | is the event whose probability we are trying to calculate.
Learning Outcome Statementscalculate and interpret conditional probabilities;
CFA® 2023 Level I Curriculum, Volume 1, Module 3
User Contributed Comments 9
|itconcepts||question" if the first dice came up as a 6, can it not be construed that the probability of six coming up again is less, therefore the remaining probability of reaching 8 is only 3/6 and not 4/6 (or perhaps even 3.167/6, as it could come up again)?|
|AusPhD||You are joking right? In case you aren't there is an important issue to bear in mind... the dice has no memory.|
|aakash1108||@itconcepts....don't brain tease us buddy!|
|TiredHand||@itconcepts you must be joking right?|
|Creep||@itconcepts, you are thinking of frequency probability. Kind of like the bird question from the section before? This is a completely different question as YOU are the one that is rolling the die. Because the die doesn't have a memory, there is a 1/6 chance of rolling a 6.|
|lenore||ok everything is actually so straightforward, why does the CFA book make everything look so complicated? its just ridiculous.|
|Allen88||Hello guys, please if any of you is studying on the CFAI books, I didn't quite understand the example of the limit order executing. In example 3, it says that if order 2 executes, it is certain that order 1 also executes because the price must pass through $10 to reach $9.75 (order 1 placed at a price limit of $10 and order 2 of $9.75). Please I really didn't understand, if someone could just help me get the logic of this. Thank you.|
|Streberli||Easy Allen, Picture this: It is april 2020 the oil price is falling you think okay I want to buy one barrel if price goes as low as 10USD. Then you think okay but if it is reaally falling hard I would buy another barrel at 9.75(so you make another limitorder at 9.75). Then the price crashes down to minus 40 dollar and both your orders get filled first for 10 then for 9.75. And there you are trying to explain to your parents why there are 2 barrels of oil standing in their livingroom.|
|Micheal11||These theories are fascinating - a pleasure to read them. Much better than reading 2!!!|
I am using your study notes and I know of at least 5 other friends of mine who used it and passed the exam last Dec. Keep up your great work!
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