A

The

- p(x
_{1}) = p(x_{2}) = p(x_{3}) = ... = p(x_{n-1}) = p(x_{n}) = p(x). That is, the probabilities for all possible outcomes are equal. - F(x
_{k}) = kp(x_{k}). That is, the cumulative distribution function for the k^{th}outcome is k times of the probability of the k^{th}outcome. - If there are k possible outcomes in a particular range, the probability for that range of outcomes is kp(X).

For example, the possible outcomes are the integers 1 to 8 (inclusive), and the probability that the random variable takes on any of those possible values is the same for all outcomes (i.e., it is uniform).

If a continuous random variable is equally likely to fall at any point between its maximum and minimum values, it is a

- The probability density function is: f(x) = 1/(b - a) for a ≤ x ≤ b; or 0 otherwise.
- The cumulative density function is: F(x) = 0 for x ≤ a; (x - a)/(b - a) for a ≤ x ≤ b; 1 for x ≥ b.

- The probability density function is a horizontal line with a height of 1/(b-a) over a range of values from a to b.
- The cumulative density function is a sloped line with a height of 0 to 1 over a range of values from a to b, and is a horizontal line with a height of 1 when the value of the variable equals or exceeds b.

For example, with a = 0 and b = 8, f(x) = 0.125. If this density is graphed, it will plot as a horizontal line with a value of 0.125.

To find the probability F(3) = P(X ≤ 3), find the area under the curve graphing the probability density function, between 0 and 3 on the x-axis. The middle line of the expression for the cumulative probability function is:

F(x) = 0 for x ≤ a; (x - a)/(b - a) for a < x < b; 1 for x ≥ b

For a continuous uniform random variable, the mean is given by μ = (a + b)/2 and the variance is given by σ

got2pass: why is the variance for the continuous uniform random variable divisible by 12? |

markh: that's the definition. check any stats textbook. |

apiccion: No, it's not by definition.You can work it out algebraically from the definition of variance. You will need to know the formula for the sum of squares and sum of the counting numbers: http://www.cs.ecu.edu/~hochberg/fall2002/class10/fslide1.html Notice the denominators of the two formulas when multiplied together give 12. |

tschorsch: you can move the distribution up or down and the variance will be the sameassume L = b-a take the interval -L/2 to L/2 instead the variance is the average of the (x-mean(x))² since in our case mean(x) is 0 the variance average is just value of x² over the interval -L/2 to L/2 the average is the same above and below x=0 so the area from 0 to L/2 is ((L/2)³ /3) or L³/24 by 2 for -L/2 to 0 so the area is L³/12 divide by L to get the average you get L²/12 but L is just b-a (i.e. the length) so (b-a)²/12 is the variance note: the area under x² is calculated by the integrating x² which is x³/3, call this G(x) the area from 0 to L/2 is G(L/2) - G(0) |

AUAU: I know the formula for prob should be born in mind. Does anyone know we should memorise the variance? |

Allen88: If you type into google, variance formula for continuous uniform distribution derivation, click on, statistics for business and financial economics-google result, scroll down a little and you'll see the derivation for both the mean and variance. |

LogicMan: nice notes. enjoy reading. comments are helpful too. |

dethepp1: For the cumulative density function: How is it possible, that the result for x = a and x = b is defined twice. In my eyes that's a mistake in the notes, but could someone submit my suggestion. It should state F(x) for a > x the result is zero and b < x the value of F(x) is 1...... |