- CFA Exams
- CFA Level I Exam
- Topic 1. Quantitative Methods
- Learning Module 2. Organizing, Visualizing, and Describing Data
- Subject 3. Summarizing Data Using Frequency Distributions

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**CFA Practice Question**

For the grouped frequency distribution shown below, the class width is ______.

B. 5

C. 6

A. 18

B. 5

C. 6

Correct Answer: C

The class width is the distance from the lower class limit to the lower class limit. Here, the class width is 28 - 22 = 6.

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**User Contributed Comments**
12

User |
Comment |
---|---|

chbourke |
Sorry. It is 5. Because is the clas width is the distance from the lower class limit to HIGH class limit. Here, the class width is 27 - 22 = 5 or 28 - 33 = 5 |

Rotigga |
No, 6 is correct. Just count: 22, 23, 24, 25, 26, 27-- that's six numbers. |

gaur |
it is 6. Remember frequency should be non-exclusive and non-overlapping. |

Sumit14 |
both the boundary values should be taken into account while counting |

Ioannis |
The number of natural numbers between N and M where M>N is M-N+1 so 27-22+1=6 |

JKiro |
"interval" must be all-inclusive & non-overlapping |

duongth307 |
Class width = (Highest - Lowest) / No. of class = (57 - 22)/6 = 5.833 or 6 (as the nearest) |

DutchNadja |
page 245 of the bible |

ciji |
is this class war going on ? |

Saxonomy |
**Throws pie in ciji's face** |

Shaan23 |
Duongth....you're kind of correct....you have to use the Class Bounderies and NOT the class limits...you guys should see a question on class bounderies if you havent yet... (57.5 - 21.5) / 6 = 6 |

Sm7272 |
Page 375 of the Bible : Interval width = Range / no. Of intervals , rounded up. (57-22)/6 = 35/6 which shall be rounded up. |