- CFA Exams
- CFA Level I Exam
- Topic 1. Quantitative Methods
- Learning Module 5. Sampling and Estimation
- Subject 5. Confidence Intervals for the Population Mean and Selection of Sample Size
CFA Practice Question
100 items are sampled from a normal distribution. The sample mean is 10 and the sample standard deviation is 2; a 95% confidence interval for the sample mean must lie between ______.
B. 9.324 and 10.676
C. 9.108 and 10.892
A. 9.608 and 10.392
B. 9.324 and 10.676
C. 9.108 and 10.892
Correct Answer: A
User Contributed Comments 7
User | Comment |
---|---|
aigulb | 10+-1.96*2/100^.5 1.96*2/100^.5=0.392 10-0.392=9.6 while 10+0.392=10.392 |
vinooka | since we don't know the population standard deviation, are we not supposed to use t-tables instead? |
stevecfa | the sample size is 100, way over 30 so the z-value is very close the t-value. |
johntan1979 | Keyword is "normal distribution". Whenever you see that, Z is first choice. |
Shaan23 | Kind of odd cause in the notes it says if the population variance is normally distributed and the population variance is unknown use the t test IRRESPECTIVE of the sample size. |
Shaan23 | Add on to my comment. It doesnt state in the question if the pop variance is known or unknown...maybe thats why they use z.... |
Shaan23 | So people read my previous two comments. The first comment is straight from the notes and is true. Use the t test. When using the t test when using the t table with n=100 it is very close to the Z score because of the large sample. So in conclusion go with the notes and know how to use each test. |